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Square Pyramid Volume Calculator

Calculate the volume of a square pyramid with one-third base squared times height. Includes the formula, a worked example, and reference sizes for the Great Pyramid of Giza.

Perpendicular height


Calculate volume of pyramid

Formula

textvolume=frac13timestextbaseareatimestextheight\\text{volume} = \\frac{1}{3} \\times \\text{base area} \\times \\text{height}

For a square pyramid with base edge a and height h:

textvolume=frac13a2h\\text{volume} = \\frac{1}{3} a^2 h

Worked example

Calculate the volume of a square pyramid with base edge 8 cm and height 12 cm:

textbasearea=82=64textcm2\\text{base area} = 8^2 = 64 \\text{ cm}^2textvolume=frac13times64times12=frac13times768=256textcm3\\text{volume} = \\frac{1}{3} \\times 64 \\times 12 = \\frac{1}{3} \\times 768 = 256 \\text{ cm}^3

Result: 256 cm³

How to use

  1. Enter the base edge (for square pyramid) or base area
  2. Enter the height
  3. Click "Calculate" to see the volume

Pyramid types

  • Square pyramid: Base is a square
  • Triangular pyramid: Base is a triangle (tetrahedron)
  • Rectangular pyramid: Base is a rectangle
  • Regular pyramid: Base is a regular polygon

Slant height

The slant height l (distance from apex to midpoint of a base edge) relates to height h and base half-width a/2:

l=sqrth2+left(fraca2right)2l = \\sqrt{h^2 + \\left(\\frac{a}{2}\\right)^2}

Common use cases

  • Architecture and construction
  • Engineering design
  • Manufacturing
  • Packaging design
  • Volume estimation

FAQ

What is the volume of a cone? Similar: frac13pir2h\\frac{1}{3} \\pi r^2 h, where the base is a circle.

How does pyramid volume compare to a prism? A pyramid has exactly one-third the volume of a prism with the same base and height.

Can I calculate the surface area? Yes: base area + (perimeter × slant height) / 2.

What about frustums? For a truncated pyramid, the volume is frach3(A1+A2+sqrtA1A2)\\frac{h}{3}(A_1 + A_2 + \\sqrt{A_1 A_2}) where A₁ and A₂ are the base areas.

Is the formula the same for all pyramids? Yes, frac13timestextbaseareatimestextheight\\frac{1}{3} \\times \\text{base area} \\times \\text{height} works for any pyramid.

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